Map family’s table column to Inventor property

<?xml encoding=”UTF-8″>By Adam Nagy

When trying to figure out how to do something in the Inventor API, then almost always the best way to go is: do it in the UI, investigate in the API.

So I registered in the Content Center my own part, created a SIZE property then mapped it to Project.Description (Design Tracking Properties:Description):

Now using the API I can find out how the SIZE property got mapped to Project.Description property:

Public Sub CCtest()
Dim cc As ContentCenter
Set cc = ThisApplication.ContentCenter
Dim ctvn As ContentTreeViewNode
Set ctvn = cc.TreeViewTopNode. _
ChildNodes("Features"). _
ChildNodes("English"). _
ChildNodes("Block")
Dim cf As ContentFamily
Set cf = ctvn.Families(1)
Dim ctc As ContentTableColumn
Set ctc = cf.TableColumns("Size")
If ctc.HasPropertyMap Then
Dim psid As String
Dim pid As String
Call ctc.GetPropertyMap(psid, pid)
Debug.Print "PropertySetId = " & psid
Debug.Print "PropertyId = " & pid
End If
End Sub

Result:

PropertySetId = {32853F0F-3444-11d1-9E93-0060B03C1CA6}
PropertyId = 29

So basically you just have to look for the given property set in Document.PropertySets and use its InternalName property, then look for the property inside it and use the Property‘s PropId.