By Adam Nagy
I'm migrating my LISP project to ARX. In LISP I can use (entget) to find the layout name at group code 410. How can I do the same in ARX?
Solution
You need to get the owner block of the entity and from there you can get to the layout object.
static void ArxProject_GetLayout(void)
{
ads_name name;
ads_point pt;
if (acedEntSel(L"Select an entity\n", name, pt) != RTNORM)
return;
AcDbObjectId id;
acdbGetObjectId(id, name);
AcDbEntityPointer ptrEnt(id, AcDb::kForRead);
if (ptrEnt.openStatus() != Acad::eOk)
return;
AcDbBlockTableRecordPointer ptrBTR(ptrEnt->ownerId(), AcDb::kForRead);
if (ptrBTR.openStatus() != Acad::eOk)
return;
AcDbObjectPointer<AcDbLayout> ptrLayout(ptrBTR->getLayoutId(), AcDb::kForRead);
if (ptrLayout.openStatus() != Acad::eOk)
return;
const ACHAR* layoutName;
ptrLayout->getLayoutName(layoutName);
acutPrintf(L"The layout the selected entity belongs to is %s", layoutName);
}
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